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-12n-4=6n^2
We move all terms to the left:
-12n-4-(6n^2)=0
determiningTheFunctionDomain -6n^2-12n-4=0
a = -6; b = -12; c = -4;
Δ = b2-4ac
Δ = -122-4·(-6)·(-4)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{3}}{2*-6}=\frac{12-4\sqrt{3}}{-12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{3}}{2*-6}=\frac{12+4\sqrt{3}}{-12} $
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